Math Beauty 2

(x^2)' = 2x or 2*x^2-1 or 2x^1

Therefore:

(16)' = (16 * x^0)' = 16 * 0 * x^0-1 = 0

[Yes, x goes to x^-1 but because it is multiplied by 0 it does not matter.]

Therefore:

(2x^2 +2x + 16)' = 4x + 2

Beautiful!